A semicircle is inscribed in equilateral triangle ABC, as shown …
Given: A semicircle is inscribed in equilateral triangle ABC, as shown above. Asked: If the area of the triangle is 16, what is the area of the semicircle? Area of equilateral triangle = 16 = 3√ a2/4 …
Triangle ABC is inscribed in a semicircle. What is the area of the sh ...
Area of shaded region = (semicircle's area) - triangle's area) Find base of ∆ ABC = semicircle's diameter Any triangle inscribed in a circle whose hypotenuse is the diameter of the circle is a …
Two semi-circles are drawn on adjacent sides of a square with side …
Aug 23, 2023 · Now the area of leaf in one semicircle shall be computed as in the following diagram: We divide the semicircle in the quarter circle and subtract from that the area of …
In the figure above, if semicircles A and B each have area 4pi
The radius of each semicircle is 2√2, so the diameter of each of the semicircles A and B is 4√2. The diameter of semicircle A is the length of one of the legs of the triangle, and the diameter of …
If a wire is bent into the shape of a square, then the area enclosed
5 days ago · Since the area of the square is 81, the side is 9, and thus the perimeter is 36. Since 36 is the perimeter of the semicircle, we know that, in terms of the circle’s radius, the …
D01-33 : GMAT Club Tests
Sep 9, 2025 · A semicircle with a diameter of π π has a circle inscribed right in the middle, as shown below. What is the ratio of the area of the semicircle to the area that is not covered by …
The window in the figure above consists of a rectangle and a …
Dec 17, 2025 · The window in the figure above consists of a rectangle and a semicircle with dimensions as shown. What is the area, in square feet, of the window? A) 40 + 8\pi B) 40 + …
A circle of radius 2 is inscribed in a semicircle, as shown. The area ...
A circle of radius 2 is inscribed in a semicircle, as shown. The area inside the semicircle but outside the circle is shaded. What fraction of the semicircle's area is shaded? (A) 1/2 (B) \frac …
In the figure below, N congruent semicircles lie on the diameter of a
Aug 20, 2025 · With the total area of the smaller semicircles: first you find one individual area, then multiply that area by the number of semicircles —- (N) * (d)^2 However, with the overall …
The figure above displays two semicircles, one with diameter AB …
The figure above displays two semicircles, one with diameter AB and one with diameter AC. If AB has a length of 4 and AC has a length of 6, what fraction of the larger semicircle ...